A math-only board.
So I recently graduated from Fine Arts studies and realized that I actually miss learning Math but I don't know where to start again. The last thing I remember from highschool is the very basics of calculus. Any books or websites that you might recommend? (Also, i'm quite interested in math for audio/acoustics/sound design)
Ever since that other anonymous website made a major contribution to mathematics, I feel like we should be able to do it too. I vote that we work on the Riemann Hypothesis.
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Please do! That would be awesome!
Not sure I can help...
>Ever since that other anonymous website ...
Which anonymous website?
>>60
> Which anonymous website?
I found a question on Stack Overflow about the topic of anonymous contributions to math, one of the answers pertained to a certain western anonymous forum:
https://www.wired.com/story/how-an-anonymous-4chan-post-helped-solve-a-25-year-old-math-puzzle/
The tl;dr is a post was made asking about what was the least amount of episodes to watch every ordering of episodes in the first season of The Melancholy of Haruhi Suzumiya as it was aired out of order intentionally.
For the 14 episodes you'd have to watch a minimum of 93,884,313,611 episodes for all orderings.
This was left unchecked properly until seven years later after Greg Egan proved the upper bound, which drew attention to the original lower bound post.
The important thing is that both proofs (if you call an imageboard post a proof) apply to a series of any length.
The lower bound was formalized in a paper written in October, 2018.
The link to the paper mentioned in the article is broken so here is a working one:
https://oeis.org/A180632/a180632.pdf
(Links to the archived post on the board are in the paper)
Here is the previously stated Stack question:
https://hsm.stackexchange.com/questions/3001/are-there-any-anonymous-contributions-to-mathematics-that-had-a-great-impact
Overall, a pretty interesting ordeal, though I'm not sure how surprised I am that anime would be the cause of advancements in mathematics given the audience it tends to draw.
how do i learn how to math. I have a GED understanding of math in the very normal range.
Want to be a man, and not an ape.
Please.
Try improving your understanding of logic first, if you haven't already. It is fundamental to all of mathematics.
Although I have not read it myself, I have heard good things about the "Book of Proof".
i have found some one willing to tutor me in algebra through calculus- where can I find textbooks (not pdf's, they require me to get a book) for cheap? Even if they're older, that would be fine with me.
Check out any thrift stores near you?
LOL
> sell X amount of people
This sounds like a slave trading product.
>>61
lol i mean sell to ORz
so you never really gonna be better consistently without any logic....
x
As I understand you can also apply Cantor's diagonal argument to a matrix (or well just write columns below eachother), thus proofing that you can always reduce an n-dimensional tensor to a 1 dimensional vector. Similarly, you can reduce an n-dimensional vectorspace to 1 dimension. For example, you could encode all the (natural) numbers in an n-dimensional vector in only one ("1D") number following Gödel, like this: 2^n_1*3^n2*...*p^n_i
e-d statements are rad
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$\eq$
percent signs are important
What's your favourite theorem?
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Ummm, is it normal to know a lot of these theorems offhand?
Either Gauss-Bonnet or the Theorema Egregium. Both are classical theorems related to Gaussian curvature, which is like a measure of how twisty a surface is at a point (sphere has positive curvature because it's bent in the same direction, hyperbola has negative curvature because it's bent in opposite directions, plane and cylander have 0 curvature because they're flat in a direction)
Gauss-Bonnet: if you start with a surface, and you stretch or bend it somehow, the integral of the curvature stays the same. This shows that, for instance, no matter how weirdly you stretch and bend a sphere, it stays a sphere (in some sense)
Theorema Egregium: if you keep distances between points fixed, then you also keep curvature fixed. This is why it is not possible to have a perfectly accurate map, because the paper is flat everywhere but the sphere is not flat anywhere. So any time you try to map any portion of a sphere, there will be some distortion of distances and area.
You guys are awesome. Unfortunately I don't know much. My brain is stained with dirty physics.
can you use math to predict a product's sales? like maybe a certain design and format, and how will it get X amount of people? Maybe a certain mouse design like razor?
I love math!
I love math too!
Come to Mathchan (it's not ready yet).
I've always wondered about how to get more kids into mathematics. I've even thought about writing math books aimed at children. To do that I want to read the existing literature out there. Let's compile kids' books and resources about teaching math
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customer!
http://worrydream.com/SimulationAsAPracticalTool/
>>40
>Mathematics, as currently taught, consists of the manipulation of abstract symbols. For most people, the level of abstraction makes math unpleasant or unusable as a practical tool for exploring the problems of their lives.
>The simulations represent the problem concretely, without abstractions; provide a broader context, allowing a deeper understanding of the situation
This is interesting. The way I always saw it was that abstraction is the means by which we make logical thought, and was therefore the most important takeaway from mathematics.
Certainly learning practical applications is necessary as well, but being able to abstract those applications means they can be applied to more (possibly completely unrelated) situations...
https://www.nytimes.com/2020/02/05/science/quadratic-equations-algebra.html
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Paywalled.
Can someone with access to the article, summarize shat the trick is ?
>>26
"This alternate method for solving quadratic equations uses the fact that parabolas are symmetrical.
For example, in this parabola:
y = x^2 – 4x – 5
The two solutions when y = 0 are the symmetrical points r and s, where the parabola crosses the x-axis.
The midpoint, or average, of r and s is the axis of symmetry of the parabola. We want r + s = –b, which happens when the average of r and s is –b ÷ 2. In this example: 4 ÷ 2 = 2.
The two solutions to the quadratic equation will be the axis of symmetry plus or minus an unknown amount, which we’ll call u. In this example:
r = 2 – u and s = 2 + u
To find u, we want the product of r and s to be equal to c, which in this example is –5. Rewriting r and s in terms of u:
r × s = –5
(2 – u) × (2 + u) = –5
Solving that yields 22 – u2 = –5 or u2 = 9, so u = 3 works.
The two solutions to this quadratic equation are 2 – u and 2 + u, or –1 and 5. In other words, this parabola intersects the x-axis when x = –1 and x = 5."
>>28
>Solving that yields 22 – u2 = –5 or u2 = 9, so u = 3 works.
Solving that yields 22 – u^2 = –5 or u^2 = 9, so u = 3 works.
Sorry. Copy-and-paste mistake.
Thank you for your wonderful contribution! Always love to see some real maths here.